very barebones introduction
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= Introduction
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= Introduction
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== Before starting
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In the NISQ era quantum-classical hybrid methods are better due to the limited depth, bla bla bla
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Okay, so as far as I currently know a Variational Quantum Eigensolver (VQE) is a semi-quantum way to find eigenvalues
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for a matrix.
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There has been significant research into various methods of Quantum Architecture Search (QAS),
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They currently are mostly using Hardware Efficient Ansatze. // TODO: needs facts
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(list a bunch).
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These Ansatze are optimized for relatively small connectivity, and don't keep errors into account that much.
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Most of these have been searches that are specific to the problem that is being solved,
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I want to figure out if this can be done better, by using a descriptor format of the hardware including connections
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so the Paremetrized quantum circuits (PQCs) are generally not transferrable between different problems.
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between qubits etc. is it possible to make ansatze that are better in
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- fewer parameters
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There has also been a bit of research into task-agnostic QAS, where search
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- less error prone
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can be performed once per hardware iteration instead of per problem, using proxies like expressibility
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- speed of optimisation
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and entanglement (CITE THE PAPER).
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Where maybe some finetuning can help specialise into a specific problem afterwards. (HYPOTHETICAL)
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These task-agnostic searches have yet to include things like noise, arbitrary connectivity graphs
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and allowed gate types on a per-qubit basis. And also haven't shown great scalability to architectures
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with more qubits.
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This research proposes a Task-Agnostic Evolutionary QAS implementing
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hardware constraints and noise profiles able to target circuits with a
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user-specified expressibility and entanglement to be able to mitigate the barren plateaus from
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an expressibility that's too high (cite).
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To achieve these goals a python library will be made that allows for composing various filters
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and generators together (with multithreading) to help with developing and iterating on QAS methods.
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That is what I will go and try figuring out I think
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